算是解答了我许久以来的困惑:Given ψ⇒φ, it might be p&q⇒p or p⇒p∨q . There's a question that always arises: how could we eliminate the possibility of the former while what we intend to say by the formula ψ⇒φ is the latter ?
评分 评分 评分##力所能及的篇幅是惊为天人的阅读体验(对第四章的领会非常糟糕),很难见到一部这样有魄力的著作,重新检视和问题化了一系列当代分析哲学中被默认的预设选项,并给出一份连贯而系统的另类解决方案。
评分 评分 评分算是解答了我许久以来的困惑:Given ψ⇒φ, it might be p&q⇒p or p⇒p∨q . There's a question that always arises: how could we eliminate the possibility of the former while what we intend to say by the formula ψ⇒φ is the latter ?
评分##重评 从来没读过这么牛逼的书 不想单纯用伟大来形容
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